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5th Grade · Session 10 of 10

Area with Decimals & Mixed Review

Find areas when dimensions are decimals, then tackle a mixed review covering everything from Sessions 1–9. Show every step.

A

Area — Decimal Dimensions

Multiply the decimal side lengths. Don't forget the unit².

1
Area = ?4.5 m3.2 mlength=4.5 m,width=3.2 m\text{length} = 4.5\text{ m},\quad \text{width} = 3.2\text{ m}
Area =
2
Area = ?2.75 in1.4 inlength=2.75 in,width=1.4 in\text{length} = 2.75\text{ in},\quad \text{width} = 1.4\text{ in}
Area =
3
Area = ?8.5 m4.2 mlength=8.5 m,width=4.2 m\text{length} = 8.5\text{ m},\quad \text{width} = 4.2\text{ m}
Area =
4
Area = ?6.3 cm2.5 cmlength=6.3 cm,width=2.5 cm\text{length} = 6.3\text{ cm},\quad \text{width} = 2.5\text{ cm}
Area =
B

Mixed Review

These problems mix fractions, decimals, and area. Take your time.

5
34+18\dfrac{3}{4} + \dfrac{1}{8}
=
6
2.8×3.52.8 \times 3.5
=
7
56÷13\dfrac{5}{6} \div \dfrac{1}{3}
=
8

A rectangular yard is 151215\dfrac{1}{2} feet long and 8348\dfrac{3}{4} feet wide. What is the total area?

Area =
9

Convert 114\dfrac{11}{4} to a decimal, then subtract 1.351.35 from it. What is the result?

=
10

A pool cover is 8.58.5 metres long and 4.24.2 metres wide. Fencing around the entire perimeter costs $12.5012.50 per metre. What is the total fencing cost?

=
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